The restrictive likelihood is the main likelihood of ward occasions. It states that the ratio of the probabilities of events A and B multiplied by events B is the probability that event A is dependent on event B.
The probabilities are as follows:
P (A) = 0.5 P (B) = 0.6 (a) To determine the likelihood that at least one of the two projects will succeed:
P (A B) = P (A B) = P (A B) = P (A B) = P (A B) = 0.5 + 0.6 (0.5 0.6) = 0.5 + 0.6 0.3 = 1.1 0.3 P (A B) = 0.8 As a result, the probability that at least one of the two projects will be successful is 0.8.
b) Figuring out how likely it is that only the Asian project will succeed: P (A B ′) = P (A B ′) = P (A B ′) = P (A B ′) = P (A B ′) = P (A B ′) = P (A B ′) = P (A B ′) = P (A B ′) = P (A B ′) = P (A B ′) = P (A B ′) = P (A B ′) = P (A B ′) = P
And according to Complementary Law, B B ′ = P ((A B ′)) P (A B) [Because A = A] = P (A B ′) P (A B) [Because A = A] = P (A B ′) P (A B) = P (A) P (B ′) P (A B) = P (A) P (B ′) P (A B) = P (A)
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