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Alex made a sketch for a homemade soccer goal he plans to build. The goal will be in the shape of a triangular prism. The legs of the right triangles at the sides of his goal measure 4 ft and 8 ft, and the opening along the front is 24 ft. How much space is contained within this goal?

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ProHelp
To do this you need to fill in the equation: [tex] \frac{1}{2} height*sidelength *width[/tex]. So, height = 8 ft, side length = 4 ft, and width = 24 ft. So, plugging in the numbers you get:
[tex] \frac{1}{2} (8) * 4 * 24[/tex] =
[tex]4*4*24[/tex] = 384 ft
 
Hope this helped!