Respuesta :
For any single draw,
[tex]\mathbb P(\text{white})=\dfrac6{42+6+8}=\dfrac6{56}[/tex]
[tex]\mathbb P(\text{gray})=\dfrac8{42+6+8}=\dfrac8{56}[/tex]
Drawing a white marble or a gray marble are disjoint events; only one of them can happen. So
[tex]\mathbb P(\text{white or gray})=\mathbb P(\text{white})+\mathbb P(\text{gray})-\underbrace{\mathbb P(\text{white and gray})}_0[/tex]
[tex]\mathbb P(\text{white or gray})=\dfrac6{56}+\dfrac8{56}=\dfrac{14}{56}[/tex]
Out of 224 draws, you should expect [tex]\dfrac{14}{56}\times224=56[/tex] of the marbles to be either white or gray.
[tex]\mathbb P(\text{white})=\dfrac6{42+6+8}=\dfrac6{56}[/tex]
[tex]\mathbb P(\text{gray})=\dfrac8{42+6+8}=\dfrac8{56}[/tex]
Drawing a white marble or a gray marble are disjoint events; only one of them can happen. So
[tex]\mathbb P(\text{white or gray})=\mathbb P(\text{white})+\mathbb P(\text{gray})-\underbrace{\mathbb P(\text{white and gray})}_0[/tex]
[tex]\mathbb P(\text{white or gray})=\dfrac6{56}+\dfrac8{56}=\dfrac{14}{56}[/tex]
Out of 224 draws, you should expect [tex]\dfrac{14}{56}\times224=56[/tex] of the marbles to be either white or gray.
[tex]\frac{14}{56}[/tex] × 224=56 of the marbles to be either white or gray.
Step-by-step explanation: