The sweeping second hand on your wall clock is 24cm long.
a)What is the rotational speed of the second hand? b)Find the translational speed of the tip of the second hand.
c)Find the rotational acceleration of the second hand.

Respuesta :

a. the rotational speed of the second hand is 2pi per 60 seconds.
rotational speed ( w ) = 2pi / 60 s = pi / 30 per second

b.) the translational speed of the tip of the second hand (v) = rw
v = 24 cm ( pi / 30) per second
v = 2.51 cm / s

c.  the angular acceleration is zero because the second hand angular speed is constant.

The sweeping second hand of a clock has a rotational speed of 0.10 s⁻¹. The translational speed of the tip at 24 cm from the center is 2.4 cm/s. The rotational acceleration of the second hand is 0 m/s².

The rotational speed (ω) of an object rotating around an axis is the number of turns of the object divided by time. The second hand of a clock rotates an angle of in 60 seconds.

[tex]\omega = \frac{2\pi }{60s} = 0.10 s^{-1}[/tex]

We can calculate the translational speed (v) of the tip at 24 cm (r) from the center using the following expression.

[tex]v = \omega \times r = 0.10s^{-1} \times 24cm = 2.4cm/s[/tex]

The rotational acceleration (α) refers to the change in the rotational speed over time. Since ω is constant, α is zero.

The sweeping second hand of a clock has a rotational speed of 0.10 s⁻¹. The translational speed of the tip at 24 cm from the center is 2.4 cm/s. The rotational acceleration of the second hand is 0 m/s².

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