John is playing a game of darts. The probability that he throws a dart into the center of the dart board (the Bull’s eye) is . The probability that he throws the dart into the 10-point ring is . What is the probability that he either hits a Bull’s eye or scores 10 points?
1/3
2/3
3/5
2/5
1/4




Respuesta :

Answer:

[tex]\frac{2}{5}[/tex] is the required probability.

Step-by-step explanation:

The probability P(A or B) when A and B are mutually exclusive events is P(A) + P(B)

Here A is the event hitting a Bull's eye

and B is the event  throwing dart into 10 point ring.

The probability that he throws a dart into the center of the dart board (the Bull’s eye) = [tex]\frac{1}{10}[/tex].

The probability that he throws the dart into the 10-point ring = [tex]\frac{3}{10}[/tex]

Required probability = [tex]\frac{1}{10}[/tex]+ [tex]\frac{3}{10}[/tex] = [tex]\frac{4}{10}[/tex] =  [tex]\frac{2}{5}[/tex]

Answer:

2/5

Step-by-step explanation:

Plato said it was right