cgirl5424
contestada

A gas is cooled from 365 K to 285 K while its volume changes from 12.8 L to 9.9 L. The initial pressure of the gas is 1.9 atm. The final pressure of the gas, rounded to the nearest tenth, is atm.

Respuesta :

Luan45

[tex]\mathsf{\dfrac{P_{1}\cdot V_{1}}{T_{1}}=\dfrac{P_{2}\cdot V_{2}}{T_{2}}}[/tex]


[tex]\mathsf{\dfrac{1,9\cdot 12,8}{365}=\dfrac{P_{2}\cdot 9,9}{285}}[/tex]


[tex]\mathsf{\dfrac{24,32}{365} = \dfrac{9,9\cdot P_{2}}{285}}[/tex]


[tex]\mathsf{9,9\cdot365\cdotP_{2}=24,32\cdot285}[/tex]


[tex]\mathsf{3613,5\cdot P_{2}=6931,2}[/tex]


[tex]\mathsf{P_{2}=\dfrac{6931,2}{3613,5}}[/tex]


[tex]\mathsf{\boxed{P_{2}=1,92~atm}}[/tex]


I hope you enjoy!

Answer:

1.9atm

Explanation: