morgan41000
morgan41000 morgan41000
  • 10-03-2017
  • Mathematics
contestada

Factor p^4-81 completely showing all work.

Respuesta :

surjithayer10otahza surjithayer10otahza
  • 02-10-2019

Answer:

Step-by-step explanation:

[tex]p^4-81=(p^2)^2-9^2=(p^2+9)(p^2-9)=(p^2-9(-1))(p+3)(p-3)\\=(p^2-9i^2)(p+3)(p-3)\\=(p+3i)(p-3i)(p+3)(p-3)[/tex]

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