Answer:
[tex]\:\:\left(6q+7\right)\left(2q+3\right)=12q^2+32q+21[/tex]
Table is shown below
Step-by-step explanation:
Given expression [tex]\:\:\left(6q+7\right)\left(2q+3\right)[/tex]
We have to find the product of given expression using table.
Consider the given expression [tex]\:\:\left(6q+7\right)\left(2q+3\right)[/tex]
We have to find the product of given expression [tex]\:\:\left(6q+7\right)\left(2q+3\right)[/tex]
Apply FOIL METHOD,
Multiply Each term in first bracket with each term in second bracket,
[tex]\left(a+b\right)\left(c+d\right)=ac+ad+bc+bd[/tex]
We have,
[tex]=6q\cdot \:2q+6q\cdot \:3+7\cdot \:2q+7\cdot \:3[/tex]
Simplify, we have,
[tex]=6\cdot \:2qq+6\cdot \:3q+7\cdot \:2q+7\cdot \:3[/tex]
Simplify, we have,
[tex]=12q^2+32q+21[/tex]
