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minus 2πr² both sides
S-2πr²=2πrh
divide both sides by 2πr
[tex] \frac{S-2\pi r^2}{2 \pi r} =h[/tex]

The rearrangement of the formula S = 2πrh + 2πr2 for h is [tex]h = \frac{S - 2 \pi r^2}{2 \pi r}[/tex].

Given that,

  • [tex]S = 2 \pi rh + 2 \pi r^2[/tex]
  • We have to arrange the above formula for h.

Based on the above information, the calculation is as follows:

[tex]S = 2 \pi rh + 2 \pi r^2[/tex]

Here we have to deduct [tex]2 \pi r^2[/tex] from both the sides.

Now

[tex]S - 2 \pi r^2 = 2 \pi rh[/tex]

Now divide [tex]2 \pi r[/tex] from both sides

So,

[tex]h = \frac{S - 2 \pi r^2}{2 \pi r}[/tex]

Therefore we can conclude that the rearrangement of the formula S = 2πrh + 2πr2 for h is [tex]h = \frac{S - 2 \pi r^2}{2 \pi r}[/tex].

Learn more: brainly.com/question/10726356

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