contestada

write a loop that reads positive integers from standard input and that terminates when it reads an integers that is not positive . After the loop terminates , it prints out separate by a space on a single line

Respuesta :

taskmasters
I found this loop. But it ends like this: After the loop terminates, it prints out the sum of all the even integers read. Declare any variables that are needed.

int sum=0;
int num=1;
while(num > 0){
cin >> num;
if ((num % 2)==0 & (num>0)){
sum+=num;
}
}
cout << sum;

I'm not familiar with coding but I think you can work on this loop and edit it according to your requirement.

Otras preguntas