area=length times width
area=10
length=2+√2
width=w
10=(2+√2)(w)
divide both sides by (2+√2)
[tex] \frac{10}{2+ \sqrt{2} } =w[/tex]
if we were to rationalize the dnomenator
multiply by[tex] \frac{2- \sqrt{2} }{2- \sqrt{2} } [/tex]
[tex] \frac{10(2- \sqrt{2})}{4-2 } =w[/tex]
[tex] \frac{20- 10\sqrt{2}}{2} =w[/tex]
[tex] 10- 5\sqrt{2} =w[/tex]
the width is 10-5√2 m
