A 100 g piece of aluminum is heated to 90°
c. it is then dropped into water to bring its temperature down to 20°
c. the heat transferred to water is 6300 j. what is the specific heat capacity of aluminum?
When two objects are in contact, it should
be that the heat lost is equal to what is gained by the other. From this, we
can calculate things. We do as follows:
Heat = mC(Tf-T) 6300 J = (100)(C)(90 - 20) C = 0.9 J/g °C
