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What volume of a 0.0943 M H2SO4 solution, to three sig figs, is needed to neutralize 161.2 mL of a 0.0158 M LiOH solution given the following reaction?

[tex]H_{2}SO_{4}+2 LiOH \rightarrow 2H_{2}O+Li_{2}SO_{4}[/tex]
I was trying to use the following equation to find volume but im keep getting wrong answer
m1v1=m2v2

Respuesta :

I don't know the answer to long I just want points  so plz like and thank me jk  the answer is 12H2o