Answer:
[tex]m_3 =80^{\circ}[/tex]
Step-by-step explanation:
Given : [tex]m_5 =38^{\circ}[/tex]
[tex]m_6 =62^{\circ}[/tex]
To Find : [tex]m_3[/tex]
Solution:
[tex]m_5 + m_6 +m_7=180^{\circ}[/tex] (sum of linear pairs is 180°)
[tex]38^{\circ}+62^{\circ}+m_7=180^{\circ}[/tex]
[tex]100+m_7=180[/tex]
[tex]m_7=80^{\circ}[/tex]
Now to find [tex]m_3[/tex]
[tex]m_3 =m_7[/tex] (Alternate interior angles)
So, [tex]m_3 =m_7 =80^{\circ}[/tex]
So, Option C is correct.
Hence [tex]m_3 =80^{\circ}[/tex]
