Respuesta :

irspow
2x^2-7x-4=0

2x^2-8x+x-4=0

2x(x-4)+1(x-4)=0

(2x+1)(x-4)=0

x=-1/2, 4
garydesir1
Hi again

2x² - 7x - 4 = 0
Again, all you have to do is factor left side
(2x + 1)(x - 4) = 0
Set factors equal to 0
2x + 1 = 0 or x - 4 = 0
2x = 0 - 1 or x = 0 + 4
2x = - 1 0r x = 4
x = -1/2 or x = 4

Answer : (-1/2, 4)

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