The path traveled by a bottlenose dolphin as it jumps out of water is modeled by the equation y = −0.4x2 + 3x, where y is the height above water and x is the horizontal distance in feet. If a beam of light is shone upward at an angle modeled by the equation x + y = 10, at what height from the water's surface will the beam of light hit the dolphin?

Respuesta :

Answer:

5 feet

Step-by-step explanation:

The path traveled by a bottlenose dolphin as it jumps out of water is modeled by the equation,

[tex]y=-0.4x^2+3x[/tex]

where y is the height above water and x is the horizontal distance in feet.

If a beam of light is shone upward at an angle modeled by the equation

[tex]x+y=10[/tex]

A beam of light hit the dolphin.

So, line must be intersect path of dolphin.

Using substation method,

Substitute y=10-x into dolphin equation.

[tex]10-x=-0.4x^2+3x[/tex]

[tex]-0.4x^2+4x-10=0[/tex]

[tex]x=\dfrac{-4\pm\sqrt{4^2-4(-10)(-0.4)}}{2(-0.4)}[/tex]

[tex]x=5\text{ feet }[/tex]

[tex]y=5\text{ feet }[/tex]

Hence, The beam hit dolphin at 5 feet.

Ver imagen isyllus

Answer:

5 feet

Step-by-step explanation: