Respuesta :
7q^2 − 28 = 0
7q^2 = 28
q^2 = 28/7
q^2 = 4
q^2= 2^2
q=+ 2 and q = -2
hope that helps
7q^2 = 28
q^2 = 28/7
q^2 = 4
q^2= 2^2
q=+ 2 and q = -2
hope that helps
Answer:
Solution set for the equation is {2, (-2)}.
Step-by-step explanation:
The given equation is 7q² - 28 = 0
Now we add 28 on both the sides of the equation.
7q² - 28 + 28 = 0 + 28
7q² = 28
divide the equation by 7,
[tex]\frac{7q^{2} }{7}=\frac{28}{7}[/tex]
[tex]q^{2}=4[/tex]
[tex]\sqrt{q^{2}}[/tex] = ±[tex]\sqrt{4}[/tex]
q = ± 2
Or q = 2, (-2)
Solution set for the equation is {2, (-2)}.
