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A person on earth is observing the moon which is 238,860 miles away. The moon is a diameter of 2160 miles. What is the angle in degrees spanned by the moon's image in the eye of the beholder?
Angle =

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MissPhiladelphia
We assume that the problem above involves right triangles, wherein the diameter of the moon would be the height and the distance from Earth would be the base. By finding the desired angle, we used the tangent function:

tan (theta) = 2160 / 238860
theta = tan -1 *( 2160 / 238860) = 0.516 degrees

Therefore the angle in the eye of the beholder would be half a degree.


ashishdwivedilVT

The angle spanned by the moon's image in the eye of the beholder is 0.518°.

Suppose the angle spanned by the moon's image in the eye of the beholder is α.

How to compare the moon's image with a right-angle triangle?

The base of the right triangle will be the distance between the earth and the moon i.e. 238,860 miles.

The perpendicular of the right triangle will be the diameter of the moon i.e. 2160 miles.

So, [tex]tan \alpha = \frac{2160}{238860}[/tex]

[tex]\alpha = tan^{-1} \frac{2160}{238860}[/tex]

[tex]\alpha =0.518[/tex]°.

Therefore, the angle spanned by the moon's image in the eye of the beholder is 0.518°.

To get more about right triangles visit:

https://brainly.com/question/22364396

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