For titration procedures, it is important to determine the chemical reaction involved. For this problem, the reaction would be:
KOH + HCl = KCl + H2O
We calculate as follows:
.02787 L ( 0.8186 M ) ( 1 mol KOH / 1 mol HCl ) = 0.0228 mol KOH
MOlarity = 0.0228 / 0.05 = 0.46 M KOH