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If the car speeds up at a steady 1.6 m/s2 , how long after starting is the magnitude of its centripetal acceleration equal to the tangential acceleration?

Respuesta :

MissPhiladelphia
Based on internet sources, the basic formulas are: v^2/r = (at)^2/r = a ==> at^2 = r ==> t = sqrt(r/a). 

Assuming the missing units are mutually compatible, as in the following example, they don't need to be known. 
Acceleration = 1.6 cramwells/s^2 
Radius = 150 cramwells 
t = sqrt(150/1.6) = 9.68 s.

I hope this helps.

The time period should be 9.68 seconds.

Calculation of time taken:

[tex]V^2 \div R = a\\\\V^2 \div 150 = 1.6[/tex]

V = 15.5 m/sec

Now

[tex]v = a\times t\\\\1.5.5 = 1.6\times t[/tex]

t = 9.68 sec

Here r should be the radius

The speed should be 1.6

Learn more about speed here: https://brainly.com/question/17052831

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