Solve for x.
x² + 10x + 25 = 27
a)​​ ​ x=−10±33√ ​

b) x=−5±33√

​​c) ​ x=−10±93√ ​

​​d) ​ x=−5±93√ ​

Respuesta :

x² + 10x + 25 - 27 = 0
x² + 10x - 2 = 0

Using quadratic formula:

[tex]x = \frac{-10 +_- \sqrt{100 - 4(-2)}}{2}[/tex]
[tex]= \frac{-10 +_- \sqrt{108}}{2}[/tex]
[tex]= \frac{-10 +_- 6\sqrt{3}}{2}[/tex]
[tex] = -5 +_- 3\sqrt{3}[/tex]

[tex]x = -5 + 3\sqrt{3}[/tex] or [tex]x = -5 - 3\sqrt{3}[/tex]

Answer:

B.  x = -5 +- 3 sqrt(3)

Step-by-step explanation:

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