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Use this technique to find a formula for the intensity I of a sound, in terms of the sound level β and the reference intensity I0. There will be a quantity (10 dB) involved in your calculations. When you enter your answer, leave off the unit dB.

Respuesta :

Answer:

[tex]I = I_o (10^{\frac{\beta}{10}})[/tex]

Explanation:

As we know that sound level is given as

[tex]\beta = 10 Log (\frac{I}{I_o})[/tex]

so here we have

[tex]\frac{\beta}{10} = Log(\frac{I}{I_o})[/tex]

now we can take anti log both sides

[tex]10^{\frac{\beta}{10}} = \frac{I}{I_o}[/tex]

so we have

[tex]I = I_o (10^{\frac{\beta}{10}})[/tex]

so above is the expression for the intensity of sound in terms of reference intensity and sound level

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