[tex]6y^2 + 13y + 15 : \text{Factor}[/tex]
In general, given [tex]a{x}^{2}+bx+c[/tex] the factored form is:
[tex]a(x- \dfrac{-b+ \sqrt{b^2-4ac} }{2a})(x-\dfrac{-b- \sqrt{b^2-4ac}}{2a} [/tex]
In this case, a=6, b=13 and c=15.
[tex]6(y- \dfrac{-13+ \sqrt{13^2-4*6*15}}{2*6})(y- \dfrac{-13- \sqrt{13^2-4*6*15}}{2*6}) [/tex]
[tex]6(y- \dfrac{-13+ \sqrt{191i} }{12}(y-\dfrac{-13- \sqrt{191i} }{12}[/tex]