kingdiablo334
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Which of the following is the change in energy of an atom emitting a photon of wavelength of 4.35 meters? [Planck's constant, h = 6.626 × 10-34 Js, c = 2.998 × 108 meters/second] a)1.986 × 10-25 joules b) 2.823 × 10-34 joules c)9.614 × 10-42 joules d)4.567 × 10-26 joules

Respuesta :

charkey1126
I really think it is d

Answer:

d) [tex]4.567 * 10^{-26}[/tex] joules

Explanation:

  • Energy of the photon having wavelength is given as:

                 

  • [tex]E = \frac{h*c}{wavelength}[/tex]
  • h = 6.626 × 10-34 ,  c = 2.998 × 108 meters/second , wavelength = 4.35

                  [tex]E = \frac{(6.626*10^{-34})(2.998*10^{8})}{4.35}[/tex] = [tex]4.567 * 10^{-26}[/tex] Joules

                 

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