A worker at the zoo calculates the amount of fish, in pounds, needed in the weekly diet of an eagle and a bear.

·The eagle eats 6 pounds of food each week, and 60% of that weight must be fish.
·The bear eats 105 pounds of food each week, and 25% of that weight must be fish.

PART A
What is the total number of fish, in pounds, that the eagle and bear should eat each week? Round your answer to the nearest hundredth of a pound.

PART B
The zoo increases the amount of food that the bear eats each week to 115 pounds. What is the percent increase in the amount of food that the bear eats each week? Round your answer to the nearest tenth of a percent.

Part A

Eagle = 6 lbs * 60%
= 6 * 0.6
= 3.6 pounds

Bear = 105 lbs * 25%
= 105 * 0.25
= 26.25 pounds

3.6 + 26.25 = 29.85 pounds

Part B

Percent Increase = Change/Original * 100
= 10/105 * 100
= 9.52%

Answer Link

facundo3141592 facundo3141592 · Answer 2 · 2022-02-04T12:37:30+01:00

The solutions are:

A) The animals eat 29.85 lb of fish,
B) It would be an increase of 9.5%

How to work with percentages?

A) So we know that the eagle eats 6 pounds of food, and we know that 60% of that must be fish, so the eagle eats:

(60%/100%)*6 lb = 0.6*6lb = 3.6 lb

And the bear eats 105 lb of food, and 25% of that must be fish, so the bear eats:

(25%/100%)*105 lb = 0.25*105 lb = 26.25 lb

The total amount of fish that they consume together is:

3.6lb + 26.25lb = 29.85 lb

B) In this case, we take the original quantity of food that the bear ate as our 100%.

105 lb = 100%

Then what percentage does 115lb represent?

We can write:

115 lb = X

Now we can take the quotient between these two equations:

(115 lb)/(105 lb) = X/(100%)

Solving for X we get:

100%*(115 lb)/(105 lb) = 109.5%

This means that the increase, in percentage, was a 9.5%

If you want to learn more about percentages, you can read:

https://brainly.com/question/843074