Answer with explanation:
Mean of the Normal Distribution = 8
Standard Deviation = 4
50% of the students practice between 5.3 hours to 10.7 hours.
→Drawing the normal Distribution Curve,and Observing
→→→50 % of population lie on both side of mean.
Total Population = 16→∵ mean=8
When curve is symmetrical, Mean = Mode =Median
→→→Population which lie on left of 5.3 can be calculated as
Between 1 standard deviation from both side of mean lie 68% of Data.
So, Between 4 to 8, lie 34% of Data.
Between 4-5.3, % of data lie , [tex]\frac{34\times 1.3}{4}=11.05%[/tex] of Data.
Between 0-4 lie , [tex]\frac{32}{2}=16%[/tex] of Data.
So,% of Data value ,that is population that lie on left of 5.3 hours =16+11.05=27.05%
So, Percentage of Population which lie on left of 5.3,that is study less than 5.3 hours each week = 33.125%