Respuesta :

morgaine816
[tex] S_{n} = \frac{ a_{1}(1- r^{n}) }{1-r} [/tex] [tex] a_{1} = 100000, r=1.03, n=5[/tex]
[tex] S_{5} = \frac{100000(1- 1.03^{5}) }{1-1.03} = \frac{100000(-.159)}{-.03} =530,000[/tex]

So after 5 years she is making $530,000.

Hope that helps

Answer:

Starting salary of Wen = $100,000

Increment in salary every year or rate of increase = 3%

[tex]S_{5}[/tex] is salary after 5 years.

we will use the formula of amount here, as Salary increase that is interest is compounded annually.

[tex]A_{5}=P*[1+\frac{R}{100}]^5\\\\S_{5}=100000*[1+\frac{3}{100}]^5\\\\S_{5}=100000*(1.03)^5\\\\ S_{5}=100000*1.1592740743\\\\S_{5}=115927.40743[/tex]

So, [tex]S_{5}[/tex] is salary after 5 years which is equal to =$115,927.50(approx)

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