Sarah wants to hang a mirror in her room. The mirror and frame must have an area of 15 square feet. The mirror is 3 feet wide and 4 feet long. Which quadratic equation can be used to determine the thickness of the frame, x?

Sarah wants to hang a mirror in her room The mirror and frame must have an area of 15 square feet The mirror is 3 feet wide and 4 feet long Which quadratic equa class=

Respuesta :

4-y×3-v=x is an equation.
Hope it helps!

Answer:

[tex]4x^2+14x-3=0[/tex]

Step-by-step explanation:

We have been given that the mirror is 3 feet wide and the thickness of the frame is x, so width of the frame would be [tex]x+x=2x[/tex].

The width of mirror with frame would be [tex]2x+3[/tex].

Similarly, the length of the frame would be [tex]x+x=2x[/tex] and the length of mirror with frame would be [tex]2x+4[/tex].

We know that area of rectangle is width times length, so area of frame with mirror would be [tex](2x+3)(2x+4)[/tex].

We are told that The mirror and frame must have an area of 15 square feet, so we can equate our equation with 15 as:

[tex](2x+3)(2x+4)=15[/tex]

Upon simplifying our equation, we will get:

[tex]4x^2+8x+6x+12=15[/tex]

[tex]4x^2+14x+12=15[/tex]

[tex]4x^2+14x+12-15=15-15[/tex]

[tex]4x^2+14x-3=0[/tex]

Therefore, our required equation would be [tex]4x^2+14x-3=0[/tex].