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(2^8 ⋅ 3^−5 ⋅ 6^0)^−2 ⋅ 3 to the power of negative 2 over 2 to the power of 3, whole to the power of 4 ⋅ 2^28 (5 points) Write your answer in simplified form

Respuesta :

start by looking at simplifying the smaller problems 

anything to the power zero is 1[tex] 6^0 = 1[/tex]

next apply the power of a power rule... multiply the powers 

[tex](2^8\times 3^{-5} \times 1 )^{-2} = 2^{8\times -2}\times 3^{-5 \times -2}[/tex]

which becomes 

[tex]2^{-16}\times 3^{10}[/tex]

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