Answer-
The height of the triangular base of the pyramid is [tex]9\sqrt3[/tex] in
Solution-
The base of a solid oblique pyramid is an equilateral triangle with a base edge length of 18 inches.
i.e the side length of an equilateral triangle is 18 inches.
from properties of equilateral triangle we know that,
[tex]Height=\dfrac{\sqrt3}{2}\times Side[/tex]
Putting the values,
[tex]Height=\dfrac{\sqrt3}{2}\times 18=9\sqrt3[/tex]
Therefore, the height of the triangular base of the pyramid is [tex]9\sqrt3[/tex] in
