Let x = the width
it says, "The length of a rectangle is 4 less than 3 times the width." write that as:
L = 3x - 4
If the perimeter is 40, find the dimensions of the rectangle.
We know: 2L + 2W = 40
Substitute (3x-4) for L and x for W
2(3x-4) + 2x = 40
6x - 8 + 2x = 40; multiplied what's inside the brackets
6x + 2x = 40 + 8; do some basic alegbra to find x; (added 8 to both sides)
8x = 48
x = 48/8
x = 6 which is the width
It said that L = 3x - 4, therefore:
L = 3(6) - 4
L = 18 - 4
L = 14; is the length
Check our solutions in the perimeter:
2(14) + 2(6) =
28 + 12 = 40