Respuesta :

irspow
This is of the form:  (a^2-b^2)  called a difference of squares, which means each term is a perfect square.  Differences of squares always factor to:

(a+b)(a-b)  in this case:

(3x^2+15y^4)(3x^2-15y^4)  which if we factor out the 3s is

3(x^2+5y^4)*3(x^2-5y^4)

9(x^2+5y^4)(x^2-5y^4)  and this cannot be factored any further unless we use imaginary numbers ±i√5

9(x^2+5y^4)(x-(i√5)y^2)(x+(i√5)y^2)
thurix19
The answer is 9x^4 - 225y^8 = 9(x^2+5y^4)(x^2 - 5y^4)
Answer: 9(x^2+5y^4)(x^2-5y^4)


Hope this helps ya! :]

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