Answer:
1.0 mol of A should be left over.
Explanation:
We have the balanced equation:
[tex]A+2B=AB_{2}[/tex]
That means that I need 1.0 mol of A for each 2.0 moles of B to obtain 1.0 mol of [tex]AB_{2}[/tex]
Now, we have 3.0 moles of A and 4.0 moles of B reacting, so:
3.0 moles of A . [tex]\frac{1.0}{1.0}\frac{moles of AB_{2} }{moles of A}[/tex] = 3.0 moles of [tex]AB_{2}[/tex]
4.0 moles of B . [tex]\frac{1}{2} \frac{moles of AB_{2}}{moles of B}[/tex] = 2.0 moles of [tex]AB_{2}[/tex]
That means that with 3.0 moles of A and 4.0 moles of B, we can form 2.0 moles of [tex]AB_{2}[/tex] and 1.0 mole of A should be left over.
