Jill is trying to find the area of football field with the track around it at her high school. It is composed of a rectangular middle with a semicircle on each end. The rectangular field has length 130 feet and width 50 feet. What is the area of the whole thing?
A) 6500 + 625π ft2
B) 6500 + 2500π ft2
C) 6500 + 5000π ft2
D) 7125π ft2

Respuesta :

I am pretty sure it is B or C I think B

Answer:

[tex](6500+625\pi) ft^{2}[/tex]

Step-by-step explanation:

Refer the attached figure

Area of rectangle = Length * Breadth

So, area of rectangle ABCD : 130*50

                                              : 6500 square feet .

Now two semicircles are on the widths of the rectangular field .

So, diameter of the semicircles on the ends of the rectangular field = 50 feet

So, radius = diameter /2 = 50/2 = 25

Formula of area of circle = [tex]\pi r^{2}[/tex]

Area of 2 semicircles = [tex]2*\frac{\pi r^{2}}{2}[/tex]

                                   = [tex]\pi 25^{2}[/tex]

                                   = [tex]625\pi [/tex]

So, the total area of the field = 6500 square feet + 625π square feet

                                               = [tex](6500+625\pi) ft^{2}[/tex]

Hence  the area of the whole thing [tex](6500+625\pi) ft^{2}[/tex]

Ver imagen wifilethbridge