Respuesta :
2KOH(aq) + CoBr₂(aq) → 2KBr(aq) + Co(OH)₂(s)
2K⁺ + 2OH⁻ + Co²⁺ + 2Br⁻ → 2K⁺ + 2Br⁻ + Co(OH)₂
K⁺ and Br⁻ are spectator ions
2K⁺ + 2OH⁻ + Co²⁺ + 2Br⁻ → 2K⁺ + 2Br⁻ + Co(OH)₂
K⁺ and Br⁻ are spectator ions
Answer:
K+ and Br-
Explanation:
A spectator ion is an ion which remains in the same form in both the reactants and product side of a chemical reaction i.e. it does not take part in the reaction.
The reaction between KOH and CoBr2 can be represented as:
2KOH (aq) + CoBr2(aq) → 2KBr(aq) + Co(OH)2(s)
In the above equation the three aqueous solutions, KOH, CoBr2 and KBr will ionize into respective ions unlike Co(OH)2 precipitate. The Total ionic equation can be depicted as:
2K+ + 2OH- + Co2+ + 2Br- → 2K+ + 2Br- + Co(OH)2
The K+ and Br- ions remain unchanged and can be cancelled out giving the net ionic equation:
2OH- + Co2+ → Co(OH)2
Thus, K+ and Br- are spectator ions
