A vector has an x-component of length 8 and a y-component of length 2. What is the angle of the vector? (Hint: Use the inverse tangent.)

Respuesta :

θ = tan⁻¹(2/8) = 14.03°

Answer:

14.04 deg

Explanation:

Consider a right triangle ABC whose hypotenuse represent the vector itself.

x = x-component of the vector = adjacent "BC" of triangle ABC =  8

y = y-component of the vector = opposite "AC" of triangle ABC = 2

θ = angle of the vector

In triangle ABC, using trigonometric ratio

tanθ = AC/BC

tanθ = 2/8

tanθ = 0.25

θ = tan⁻¹(0.25)

θ = 14.04 deg