Respuesta :

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-III I
 NH₄⁺

V  -II
N₂O₅

I   V -II
NaNO₃
-----------------------

-3  +5  +5

Answer: Option (b) is the correct answer.

Explanation:

It is known that general charge on a hydrogen atom is +1, oxygen atom is -2, and sodium atom is +1.

Hence, oxidation number of nitrogen atom in the given species or compounds is as follows.

  • [tex]NH^{+}_{4}[/tex]

                     x + 4(1) = 1

                         x = 1 - 4

                            = -3

  • [tex]N_{2}O_{5}[/tex]

                       2x + 5(-2) = 0         (since total charge on the molecule is zero)

                          x = +5

  • [tex]NaNO_{3}[/tex]

                      1 + x + 3(-2) = 0

                            x = +5

Thus, we can conclude that the oxidation numbers of nitrogen in NH4+, N2O5, and NaNO3 are -3, +5, +5 respectively.

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