The correct answer is: Revolution (The tangential speed of Mars' revolution is greater than that of Mars' rotation).
Explanation:
Given data:
Radius-of-Mars = r = [tex]3.4 * 10^6[/tex] m
Distance-between-Sun-and-Mars = d = [tex]2.3 * 10^{11}[/tex] m
Now let us first calculate the Mars' rotation:
One complete rotation of Mars = 2πr = 2π([tex]3.4*10^6[/tex]) = [tex]21.36 * 10^6[/tex] m
Tangential speed of Mars' rotation (by taking 24hours 37 minutes in seconds (88620s)—as Mars takes that many seconds to complete one rotation) = [tex]\frac{21.36 * 10^6m}{88620} = 241.02 \frac{m}{s}[/tex]
Now let's calculate the Mars' revolution (around Sun):
One complete revolution of Mars around Sun = 2πd = 2π([tex]2.3 * 10^{11}[/tex]) = [tex]1.45 * 10^{12}[/tex] m
Tangential speed of Mars' revolution (by taking 687 days in seconds (59356800s)—since Mars takes 687days to complete one revolution)= [tex]\frac{1.45 * 10^{12}m}{59356800s} = 24.42 * 10^{3}\frac{m}{s}[/tex]
So we can see that the tagential speed of:
Revolution > Rotation
[tex]24.42 * 10^{3}\frac{m}{s}[/tex] > [tex]241.02\frac{m}{s}[/tex]
Hence, the correct answer is Revolution.
