Respuesta :
The stock solution should have a molarity of 8.24 M.
Using the formula as follows;
C1V1 = C2V2
Where;
C1 = initial concentration of the stock solution
C2 = final concentration of the stock solution
V1 = initial volume of the stock solution
V2 = final volume of the stock solution
According to the information given in this question,
V1 = 25mL = 25/1000 = 0.025L
V2 = 2L
C1 = ?
C2 = 0.103M
Using the formula; C1V1 = C2V2
C1 = C2V2/V1
C1 = (0.103 × 2) ÷ 0.025
C1 = 0.206 ÷ 0.025
C1 = 8.24 M
Therefore, the stock solution should have a molarity of 8.24M.
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