What molarity should the stock solution be if you want to dilute 25.0 ml to 2.00 l and have the final concentration be 0.103 m? what molarity should the stock solution be if you want to dilute 25.0 ml to 2.00 l and have the final concentration be 0.103 m? 0.243 m 4.12 m 8.24 m 0.206 m none of the above?

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The stock solution should have a molarity of 8.24 M.

Using the formula as follows;

C1V1 = C2V2

Where;

C1 = initial concentration of the stock solution

C2 = final concentration of the stock solution

V1 = initial volume of the stock solution

V2 = final volume of the stock solution

According to the information given in this question,

V1 = 25mL = 25/1000 = 0.025L

V2 = 2L

C1 = ?

C2 = 0.103M

Using the formula; C1V1 = C2V2

C1 = C2V2/V1

C1 = (0.103 × 2) ÷ 0.025

C1 = 0.206 ÷ 0.025

C1 = 8.24 M

Therefore, the stock solution should have a molarity of 8.24M.

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