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How many grams of methane gas (CH4) are in a 15.8-liter sample at 1.2 atmospheres and 27°C? Show all work used to solve this problem.

Respuesta :

AbhiGhost
Converting temperature to kelvin, 
T = 273 + 27 = 298 K

Using ideal gas equation,
PV = nRT 
1.2 x 15.8 = n x 0.082 x 298
n = 0.776 moles.

Therefore mass of methane gas= moles x molar mass 
                                                   =  0.776 x 16 = 12.416 grams.

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