Respuesta :

mspeople
Let's find the factors of 32 and 72:

32=2*4*4  72=6*6*2 
Therefore both of the radicals can be simplified into [tex]16 \sqrt{2} [/tex] and [tex]12 \sqrt{2} [/tex]. Now adding them we get [tex]28 \sqrt{2} [/tex]
irspow
4√32+2√72

4√(2*2*2*2*2)+2√(2*2*2*3*3)

4√(16*2)+2√(4*9*2)  moving out all of the perfect squares...

4*4√2+2*2*3√2

16√2+12√2

(16+12)√2

28√2

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