Answer: 81.33 square units
Step-by-step explanation:
Given sides of triangle = 12,14 and 16 are the a,b and c respectively.
Thus the perimeter of triangle [tex]=a+b+c=12+14+16=42[/tex]
The semi perimeter of triangle [tex]s=\frac{42}{2}=21[/tex]
By Heron's formula
Area of triangle = [tex]\sqrt{s(s-a)(s-b)(s-c)}[/tex]
[tex]=\sqrt{21(21-12)(21-14)(21-16)}\\\\=\sqrt{21(9)(7)(5)}\\\\=\sqrt{6615}\\=81.3326\approx81.33\text{ square units}[/tex]
The area of triangle =81.33 square units.
