Answer with explanation:
→ m∠AFD=90°
→ m∠AFB=31°=m∠CFD--------[Given]----(1)
→m ∠BFC=m ∠DFE-------[Given]
⇒m∠AFB + m ∠BFC +m ∠CFD=90°--------[Given]
⇒31°+ m ∠BFC +31°=90°-------[Using 1]
⇒m ∠BFC =90° -62°
⇒m ∠BFC = 28°
⇒m ∠BFC = 28°=m ∠D FE
⇒m ∠C FE=m ∠D F C+m ∠D FE
= 31° +28°
=59°
