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Physical therapists know as you soak tired muscles in a hot tub, the water will cool down as you heat up. If a 67.9 person at 37.1 oC immerses in 50.2 kg of water at 40.5o C, the equilibrium temperature is 38.7 oC. What is the specific heat of the person? Use 4.186 kJ/kgoC for the specific heat of water. Answer to 3 significant figures in kJ/kgoC .

Respuesta :

TammyP
Q1=Q2
m1c1(t-t1)=m2c2(t2-t)
67.9kg * c1* (38.7°C-37.1°C)=50.2kg * 4186 J/kg°C * (40.5°C-38.7°C)
67.9kg* c1 * 1.6°C = 50.2kg * 4186 J/kg°C * 1.8°C
108.64 kg°C * c1 = 378246.96 J
c1 = 378246.96J /108.64kg°C
c1=3481.65 J/kg°C

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