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The path of a flying fish as it made its approach to the surface of the ocean and flew out of the water is represented by the quadratic function h(t) = -t2 + 6t - 5, where t represents the time, in seconds, and h(t) represents the fish's height and depth, in feet. Graph the function using the graphing calculator. To the nearest second, how long was the fish out of the water?

Respuesta :

irspow
h(t)=-t^2+6t-5

t^2-6t+5=0

t^2-t-5t+5=0

t(t-1)-5(t-1)=0

(t-1)(t-5)=0

t=1 and 5

So the time spent out of the water is 5-1=4 seconds.

The function is plotted using the graphing calculator and the time, fish is out of the water is 4 seconds.

What is a quadratic equation?

A quadratic equation is a second-order polynomial equation in a single variable x as ax^2+bx+c=0 with a ≠ 0 . A quadratic equation as an equation of degree 2, meaning that the highest exponent of this function is 2.

For the given situation,

The quadratic function [tex]h(t) = -t^2 + 6t - 5[/tex]

Plot this function in the graph as shown.

The intersection of the parabola and x-axis is at [tex](1,0)[/tex] and [tex](5,0)[/tex].

These points represents the time t.

Thus the value of time t is 1 and 5.

Thus the time, fish is out of the water is

⇒ [tex]5-1=4[/tex]

Hence we can conclude that the function is plotted using the graphing calculator and the time, fish is out of the water is 4 seconds.

Learn more about quadratic equation here

https://brainly.com/question/12187987

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