To solve this, we assume that the gas is an ideal gas. Then, we can
use the ideal gas equation which is expressed as PV = nRT. At a constant
temperature and number of moles of the gas the product of PV is equal to some
constant. At another set of condition of temperature, the constant is still the
same. Calculations are as follows:
P1V1 =P2V2
P2 = P1 x V1 / V2
P2 = 547 mmHg x 500 mL / 225 mL
P2 =1215.56 mmHg
1215.56 mmHg ( 1 atm / 760 mmHg) = 1.60 atm
Therefore, the new pressure of the gas would be 1.60 atm.
