find a model for simple harmonic motion if the position at t=0 is 0 the amplitude is 5 centimeters and the period is 4 seconds

Respuesta :

d = 5sin(πt) 
hope this helped

Answer:

y = 5sin[tex](\frac{x}{2})[/tex]

Step-by-step explanation:

Since harmonic motion is represented by the sine wave equation.

y = a sin (bx)

where a = amplitude

period = [tex]\frac{2\pi}{b}[/tex]

Amplitude of the harmonic motion is given as 5 and period is 4 seconds.

so a = 5

and 4 = [tex]\frac{2\pi}{b}[/tex] ⇒ b = [tex]\frac{2\pi}{4}[/tex]

b = [tex]\frac{\pi}{2}[/tex]

Now we replace the values of a and b in the sine equation

y = 5sin[tex](\frac{x}{2})[/tex]