Respuesta :
(a) To create a probability distribution table, we need to calculate the probability of each outcome by dividing the frequency (f) by the total number of games played.
Touchdowns scored (x) | Number of games (f) | Probability (P)
----------------------|---------------------|----------------
0 | 8 | 8/28 ≈ 0.286
1 | 9 | 9/28 ≈ 0.321
2 | 7 | 7/28 ≈ 0.250
3 | 4 | 4/28 ≈ 0.143
(b) To find the probability of Luis scoring more than 1 touchdown, we sum the probabilities of the outcomes where x > 1.
P(x > 1) = P(x = 2) + P(x = 3) = 0.250 + 0.143 = 0.393
Therefore, the probability of Luis scoring more than 1 touchdown is approximately 0.393 or 39.3%.
(c) To find the estimated value of the number of touchdowns Luis scores, we multiply each touchdown value by its corresponding probability and sum the results.
Estimated value = (0 * 0.286) + (1 * 0.321) + (2 * 0.250) + (3 * 0.143) ≈ 0.857
Therefore, the estimated value of the number of touchdowns Luis scores is approximately 0.857 or 0.857 touchdowns per game.
Touchdowns scored (x) | Number of games (f) | Probability (P)
----------------------|---------------------|----------------
0 | 8 | 8/28 ≈ 0.286
1 | 9 | 9/28 ≈ 0.321
2 | 7 | 7/28 ≈ 0.250
3 | 4 | 4/28 ≈ 0.143
(b) To find the probability of Luis scoring more than 1 touchdown, we sum the probabilities of the outcomes where x > 1.
P(x > 1) = P(x = 2) + P(x = 3) = 0.250 + 0.143 = 0.393
Therefore, the probability of Luis scoring more than 1 touchdown is approximately 0.393 or 39.3%.
(c) To find the estimated value of the number of touchdowns Luis scores, we multiply each touchdown value by its corresponding probability and sum the results.
Estimated value = (0 * 0.286) + (1 * 0.321) + (2 * 0.250) + (3 * 0.143) ≈ 0.857
Therefore, the estimated value of the number of touchdowns Luis scores is approximately 0.857 or 0.857 touchdowns per game.
