Two equal masses A and B are attached to a light inextensible string passing over a smooth light pulley as shown in the diagram attached. The mass B is moved down, held stationary, and released. What would be the subsequent motion of B?

Would B move back to its original position? ( If not, why?)

If the masses of A and B are equal, and there is no friction or air resistance, then mass B will remain stationary after it is released. This is because the forces acting on the system are balanced.

Looking at the state before the release, moment of release, and after the release:

Before the release:

A is pulled up, and B is pulled down.
The tension in the string is the same on both sides since the masses are equal.

Moment of release:

A exerts a force pulling upwards, and mass B exerts a force pulling downwards.
Since the masses are equal, these forces are balanced.

After the release:

B does not experience any net force pulling it in either direction since the forces are balanced.
Therefore, B remains stationary.

Learn more about net force here: https://brainly.com/question/14361879

Two equal masses A and B are attached to a light inextensible string passing over a smooth light pulley as shown in the diagram attached. The mass B is moved down, held stationary, and released. What would be the subsequent motion of B?Would B move back to its original position? ( If not, why?)​

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Two equal masses A and B are attached to a light inextensible string passing over a smooth light pulley as shown in the diagram attached. The mass B is moved down, held stationary, and released. What would be the subsequent motion of B?

Would B move back to its original position? ( If not, why?)