12 + 14 = 26 balls total
probability of picking a red one first = 14/26 reduces to 7/13
then a yellow ball second would be 12/25
probability of both happening = 7/13 x 12/25 = 84/325
Probability that the first ball drawn is a red ball if the second ball drawn is yellow = 7/13
Number of yellow balls, N(Y) = 12
Number of red balls, N(R) = 14
Total number of balls, N(Total) = 12 + 14
N(Total) = 26
Probability of picking a yellow a ball
Pr(Y) = N(Y) / N(Total)
Pr(Y) = 12/26 = 6/13
Probability of picking a red ball
Pr(R) = N(R) / N(Total)
Pr(R) = 14/26 = 7/13
Probability of the two balls are red and yellow
Pr(RnY) = 6/13 x 7/13
Pr(RnY) = 42/169
Probability that the first ball drawn is a red ball if the second ball drawn is yellow
Pr(R|Y) = Pr(RnY)/P(Y)
Pr(R|Y) = 42/169 ÷ 6/13
Pr(R|Y) = 42/169 x 13/6
Pr(R|Y) = 7/13
Probability that the first ball drawn is a red ball if the second ball drawn is yellow = 7/13
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